The NCERT book will play a significant role to excel in the 12th Physics exam. But, students cannot solve some questions and therefore look for solutions. So, in this article, you’ll get the NCERT class 12 Physics solutions for all the important questions.
The solutions are prepared by the subject experts following the updated CBSE guidelines. These physics answers will help students to solve the questions in an incisive way and write to-the-point theory answers.
Therefore, students can download the NCERT class 12 physics solutions of all the chapters in pdf format for free.
Download NCERT Class 12 Physics Solutions (All Chapters)
NCERT solutions for class 12 physics are provided for students to get an idea of how to solve questions in the upcoming class 12 physics board exams. Given below are the pdf download links of the NCERT class 12 physics solutions.
NCERT solutions for class 12 Physics subject are provided for students to get an idea of how to solve questions in the board exams. Check the table below to download the answers pdf.
|NCERT Class 12 Physics Solutions||Download PDF|
|Chapter 1||Electric Charges and Fields|
|Chapter 2||Electrostatic Potential and Capacitance|
|Chapter 3||Current Electricity|
|Chapter 4||Moving Charges and Magnetism|
|Chapter 5||Magnetism and Matter|
|Chapter 6||Electromagnetic Induction|
|Chapter 7||Alternating Current|
|Chapter 8||Electromagnetic Waves|
|Chapter 9||Ray Optics and Optical Instruments|
|Chapter 10||Wave Optics|
|Chapter 11||Dual Nature of Radiation and Matter|
|Chapter 14||Semiconductor Electronics|
|Chapter 15||Communication Systems|
NCERT Class 12 Physics Solutions: Important Questions with Solutions
Q1. When a glass rod is rubbed with a silk cloth, charges appear on both. A similar phenomenon is observed with many other pairs of bodies. Explain how this observation is consistent with the law of conservation of charge.
Ans: Rubbing produces charges of equal magnitude but of opposite nature on the two bodies because charges are created in pairs. This phenomenon of charging is called charging by friction. The net charge on the system of two rubbed bodies is zero. This is because equal amounts of opposite charges annihilate each other. When a glass rod is rubbed with a silk cloth, opposite nature charges appear on both bodies. This phenomenon is consistent with the law of conservation of energy. A similar phenomenon is observed with many other pairs of bodies.
Q2.Three capacitors of capacitances 2pF, 3pF and 4pF are connected in parallel. What is the total capacitance of the combination?
Ans: Capacitances of the given capacitors: C1 = 2 pF, C2 = 3 pF and C3 = 4 pFFor the parallel combination of the capacitors, an equivalent capacitor is given by Ceq the algebraic sum,Therefore Ceq = C1 + C2 + C3 = 2 + 3 + 4 = 9 pFTherefore, the total capacitance of the combination is 9 pF.
Q3.Guess a possible reason why water has a much greater dielectric constant (80) than say, mica (6).
Ans: Water has an unsymmetrical space as compared to mica. Since it has a permanent dipole moment, it has a greater dielectric constant than mica.
Q4. A steady current flows in a metallic conductor of a non-uniform cross-section. Which of these quantities is constant along the conductor: current, current density, electric field, drift speed?
Ans: When a steady current flows in a metallic conductor of a non-uniform cross-section, the current flowing through the conductor is constant. Current density, electric field, and drift speed are inversely proportional to the area of the cross-section. Therefore, they are not constant.
Q5. A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to plane of the coil makes an angle of 30º with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque?
Ans: Length of a side of the square coil, l = 10 cm = 0.1 m
Current flowing in the coil, I = 12 A
Number of turns on the coil, n = 20
Angle made by the plane of the coil with the magnetic field, θ = 30°
Strength of magnetic field, B = 0.80 T
Magnitude of the magnetic torque experienced by the coil in the magnetic field is given by the relation,τ = n BIA sinθ
Where, A = Area of the square coil= l × l = 0.1 × 0.1= 0.01 m2
So,τ = 20 × 0.8 × 12 × 0.01 × sin30°= 0.96 N m
Hence, the magnitude of the torque experienced by the coil is 0.96 N m.
Q6.The earth’s magnetic field varies from point to point in space. Does it also change with time? If so, on what time scale does it change appreciably?
Ans: Earth’s magnetic field changes with time. It takes a few hundred years to change by an appreciable amount. The variation in the earth’s magnetic field with time cannot be neglected.
Q7. If a toroid uses bismuth for its core, will the field in the core be (slightly) greater or (slightly) less than when the core is empty?
Ans: Bismuth is a diamagnetic substance. Hence, a toroid with a bismuth core has a magnetic field slightly greater than a toroid whose core is empty.
Q8. A capacitor is used in the primary circuit of an induction coil.
Ans: High induced voltage is used to charge the capacitor.
A capacitor is used in the primary circuit of an induction coil. This is because when the circuit is broken, a high induced voltage is used to charge the capacitor to avoid sparks.
Q9. It is necessary to use satellites for long-distance TV transmission. Why?
Ans: It is necessary to use satellites for long-distance TV transmissions because television signals are of high frequencies and high energies. Thus, these signals are not reflected by the ionosphere. Hence, satellites are helpful in reflecting TV signals. Also, they help in long-distance TV transmissions.
Q10. A person looking at a person wearing a shirt with a pattern comprising vertical and horizontal lines is able to see the vertical lines more distinctly than the horizontal ones. What is this defect due to? How to correct such a defect of vision?
Ans: In the given case, the person is able to see vertical lines more distinctly than horizontal lines. This means that the refracting system (cornea and eye-lens) of the eye is not working in the same way in different planes. This defect is called astigmatism. The person’s eye has enough curvature in the vertical plane. However, the curvature in the horizontal plane is insufficient. Hence, sharp images of the vertical lines are formed on the retina, but horizontal lines appear blurred. This defect can be corrected by using cylindrical lenses.
Class 12 Physics Chapter-Wise Summary
Chapter 1 Electric Charges and Fields Summary
In this chapter, you will study the concept of electric charges and conservation, Coulomb’s law. Also study the force between charges, and the principle of superposition and continuous charge distribution, electric field and its application, electric dipole, the concept of electric flux, Gauss’s theorem and its applications.
Chapter 2 Electrostatic Potential and Capacitance Summary
In this chapter, you will study the electric potential and its applications, potential difference, equipotential surfaces, and the electrical potential energy of charges in an electrostatic field. You will study conductors and insulators, free charges and bound charges inside a conductor. Also dielectrics and electric polarization, capacitors and capacitance, the combination of capacitors in series and in parallel, energy stored in a capacitor.
Chapter 3 Current Electricity Summary
In this chapter, you will learn the concept of electric current, and the flow of electric charges in a metallic conductor. The concept of electrical resistance, V-I characteristics, Kirchhoff’s law and its applications, potentiometer – principle and its applications, Wheatstone bridge, and meter bridge.
Chapter 4 Moving Charges and Magnetism Summary
In this chapter, you will learn the concept of the magnetic field, Oersted’s experiment, Biot – Savart law, Ampere’s law, and their applications, and solenoids, the force on a moving charge, the concept of torque, moving coil galvanometer.
Chapter 5 Magnetism and Matter Summary
This chapter explains the magnetic dipole and its moment, the concept of torque on a magnetic dipole; bar magnet as an equivalent solenoid, magnetic field lines, Earth’s magnetic field, and magnetic elements, types of magnetic substances, the concept of electromagnets and factors affecting its strength.
Chapter 6 Electromagnetic Induction Summary
This chapter explains the concept of electromagnetic induction, Faraday’s laws, induced emf and current, Lenz’s Law, Eddy currents, and types of induction.
Chapter 7 Alternating Current Summary
In this chapter, you will get to know about alternating currents, peak and RMS value of alternating current/voltage, reactance, and impedance, LC oscillations, LCR series circuit, resonance and power in AC circuits, AC generator and transformer, and wattless current.
Chapter 8 Electromagnetic Waves Summary
This chapter explains the basic idea of displacement current, electromagnetic waves and their characteristics and transverse nature. You will also learn the concept of the electromagnetic spectrum including elementary facts and their uses.
Chapter 9 Ray Optics and Optical Instruments Summary
In this chapter, you will study reflection and refraction of light, mirror formula, total internal reflection and its applications, optical fibres, thin lens formula, lens maker’s formula, the concept of magnification, and the combination of thin lenses. You will also study microscopes and astronomical telescopes and their magnifying powers.
Chapter 10 Wave Optics Summary
In this chapter you will study wavefront, Huygen’s principle, reflection and refraction of a plane wave, the concept of interference, Young’s double-slit experiment and expression for fringe width, coherent sources and sustained interference of light, diffraction due to a single slit, polarisation, plane polarised light and uses, Brewster’s law, the concept of resolving power.
Chapter 11 Dual Nature of Radiation and Matter Summary
In this chapter, you will learn about the dual nature of radiation, the photoelectric effect, Hertz and Lenard’s observations, Einstein’s photoelectric equation, and de Broglie’s relation. Davisson-Germer experiment.
Chapter 12 Atoms Summary
This chapter explains the scattering experiment of alpha-particle, Rutherford’s model of an atom, Bohr model, energy levels, and hydrogen spectrum.
Chapter 13 Nuclei Summary
This chapter explains the composition and size of the nucleus, atomic masses, isotopes, isobars, isotones, radioactivity, and radioactive particles and their properties and radioactive decay law, the mass-energy relation, nuclear fission, and fusion.
Chapter 14 Semiconductor Electronics Summary
This chapter tells you about energy bands and their I-V characteristics, diodes, and types of diodes and their characteristics and uses of diodes, junction transistors and characteristics of a transistor and application, the concept of analogue and digital signals, logic gates.
Chapter 15 Communication Systems Summary
This chapter explains the elements of a communication system, bandwidth of signals and transmission medium, propagation of electromagnetic waves, concept of wave propagation, satellite communication, and amplitude modulation.
Why VSI Jaipur for NCERT Class 12 Physics Solutions?
The reasons to follow the NCERT physics solutions of VSI Jaipur are:
- VSI’s NCERT solutions for 12th physics provide an in-depth understanding of the difficult questions.
- The solutions are prepared as per the revised CBSE curriculum.
- Students can go through the NCERT class 12 physics solutions to score well in the CBSE class 12th results.
- Develops confidence in students to write better answers in the exams.
About VSI Jaipur
VSI Jaipur provides the best 12th commerce classes for Accounts, Maths, BST and Economics subjects. By taking tuition from VSI, you can build solid concepts and get high grades in your 12th board exams. Further, if you aspire to become a CA, you can join our coaching classes and clear the CA exams on the first attempt. VSI Jaipur is the best CA Coaching in India and our students have scored the ever-highest marks in CA IPCC, Intermediate and Final exams. Moreover, our 7 students got AIR 1 in the last 10 years.
Further, we also provide the best CMA and ACCA coaching classes for all levels. So, join VSI Jaipur’s online or offline classes to get the best class 12th result and build a strong foundation for CA/CMA/ACCA.
Frequently Asked Questions
Q 1. Is NCERT enough for the upcoming CBSE Class 12 Physics exam 2023?
Ans: Yes, NCERT is enough as it covers the base of all the topics. However, students should also refer to some other reference books after completing the NCERT syllabus.
Q 2. From where can students access free NCERT class 12 Physics solutions?
Ans: The free NCERT class 12 physics solutions are available on the page above.
Q 3. How many chapters are there in Clas 12 Physics subject?
Ans: There is a total of 15 chapters that students have to study in class 12th Physics.
Q 4. How to score good marks in the Physics paper?
Ans: To score good marks in the Physics paper, students should focus on understanding the concepts. Furthermore, follow the NCERT books as it covers all the question in easy language.
Q5. What are the career opportunities after class 12th in PCM?
Ans. There are enormous career opportunities after class 12th in PCM. Students can check all these opportunities on courses after 12th page.